Appendix: Parameters to recognizers
30 May 2016As explained in LLLPG grammar features, each rule can have a recognizer form which is called by syntactic predicates &(...)
. The recognizer always has a return type of bool
, regardless of the return type of the main rule, and any action blocks {...}
are removed from the recognizer (currently there is no way to keep an action block; sorry.)
You can cause parameters to be kept or discarded from a recognizer using a recognizer
attribute on a rule. Observe how code is generated for the following rule:
LLLPG(parser) {
[recognizer { void FooRecognizer(int x); }]
token double Foo(int x, int y) @{ match something };
token double FooCaller(int x, int y) @[
Foo(1) Foo(1, 2) &Foo(1) &Foo(1, 2)
];
}
The recognizer version of Foo will accept only one argument because the recognizer
attribute specifies only one argument. Although the recognizer
attribute uses void
as the return type of FooRecognizer
, LLLPG ignores this and changes the return type to bool
:
double Foo(int x, int y)
{
Match(match);
Match(something);
}
bool Try_FooRecognizer(int lookaheadAmt, int x)
{
using (new SavePosition(this, lookaheadAmt))
return FooRecognizer(x);
}
bool FooRecognizer(int x)
{
if (!TryMatch(match))
return false;
if (!TryMatch(something))
return false;
return true;
}
double FooCaller(int x, int y)
{
Foo(1);
Foo(1, 2);
Check(Try_FooRecognizer(0, 1), "Foo");
Check(Try_FooRecognizer(0, 1, 2), "Foo");
}
Notice that LLLPG does not verify that FooCaller
passes the correct number of arguments to Foo
or FooRecognizer
, not in this case anyway. So LLLPG does not complain or alter the incorrect call Foo(1)
or Try_FooRecognizer(0, 1, 2)
. Usually LLLPG will simply repeat the argument argument list you provide, whether it makes sense or not. However, as a normal rule is “converted” into a recognizer, LLLPG can automatically reduce the number of arguments to other rules called by that rule, as demonstrated here:
[recognizer {void BarRecognizer(int x);}]
token double Bar(int x, int y) @[ match something ];
rule void BarCaller @[
Bar(1, 2)
];
rule double Start(int x, int y) @[ &BarCaller BarCaller ];
Generated code:
double Bar(int x, int y)
{
Match(match);
Match(something);
}
bool Try_BarRecognizer(int lookaheadAmt, int x)
{
using (new SavePosition(this, lookaheadAmt))
return BarRecognizer(x);
}
bool BarRecognizer(int x)
{
if (!TryMatch(match))
return false;
if (!TryMatch(something))
return false;
return true;
}
void BarCaller()
{
Bar(1, 2);
}
bool Try_Scan_BarCaller(int lookaheadAmt)
{
using (new SavePosition(this, lookaheadAmt))
return Scan_BarCaller();
}
bool Scan_BarCaller()
{
if (!BarRecognizer(1))
return false;
return true;
}
double Start(int x, int y)
{
Check(Try_Scan_BarCaller(0), "BarCaller");
BarCaller();
}
Notice that BarCaller()
calls Bar(1, 2)
, with two arguments. However, Scan_BarCaller
, which is the auto-generated name of the recognizer for BarCaller
, calls BarRecognizer(1)
with only a single parameter. Sometimes a parameter that is needed by the main rule (Bar
) is not needed by the recognizer form of the rule (BarRecognizer
) so LLLPG lets you remove parameters in the recognizer
attribute; LLLPG will automatically delete call-site parameters when generating the recognizer version of a rule. You must only remove parameters from the end of the argument list; for example, if you write
[recognizer { void XRecognizer(string second); }]
rule double X(int first, string second) @[ match something ];
LLLPG will not notice that you removed the first parameter rather than the second, it will only notice that the recognizer has a shorter parameter list, so it will only remove the second parameter. Also, LLLPG will only remove parameters from calls to the recognizer, not calls to the main rule, so the recognizer cannot accept more arguments than the main rule.